When dealing with the ideal gas, we assume that its particles have only translational kinetic energy, with three corresponding degrees of freedom. In producing the result that U = /NT, where N is the number of particles, we seem to have /T energy for each separate degree of freedom (we have a total of 3N such degrees). When we have a molecule we would also expect there to be two extra degrees of freedom, because of the movement of each atom of a pair around the other (see fig. 8.7). Then U = /NT and the specific heat is = /N, which for one gram molecule is /R cal mole deg